What will be the output of the given program?
#include<stdio.h>
void main()
{
int value=0;
if(value)
printf("well done ");
printf("Edurev");
}
a)
well done Edurev
b)
Edurev
c)

complier error
d)
None of these
Correct answer is option 'B'. Can you explain this answer?

Question

What will be the output of the given program?

#include<stdio.h>
void main()
{
int value=0;
if(value)
printf("well done ");
printf("Edurev");
}

a)
well done Edurev
b)
Edurev
c)

complier error
d)
None of these

Correct answer is option 'B'. Can you explain this answer?

Answer

As the value of variable value is zero so, it evaluates to false in the if condition.

Answer

Understanding the Program
The provided C program evaluates the variable `value` and prints output based on its condition.
Code Breakdown
- The program initializes an integer variable `value` to `0`.
- It uses an `if` statement to check if `value` is non-zero.
Condition Evaluation
- In C, a condition evaluates to `true` if the value is non-zero and `false` if it is zero.
- Since `value` is initialized to `0`, the condition `if(value)` evaluates to `false`.
Output Explanation
- The line `printf('well done ');` inside the `if` block will not execute because the condition is not met.
- The next line, `printf('Edurev');`, will execute regardless of the `if` condition, as it is outside the block.
Final Output
- Therefore, the only output of the program will be:
Edurev
Conclusion
- The correct answer is option 'B': Edurev.
This output is a direct result of the condition failing due to the initialization of `value` to `0`.

Answer

The variable value is assigned with zero ... generally system takes the binary input only .. zero means false and 1 mean true.... so that the value is false here ... when it runs the code ... if condition will be failed and runs out of the statement and print the edurev only ...

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